The CS50 Tideman solution implements a voting system that determines the winner of an election based on ranked ballots. The solution involves reading input, initializing data structures, counting first-place votes, checking for a winner, eliminating candidates, and recounting votes. The implementation includes test cases to verify its correctness.
The ranks array holds the order of candidates for the current voter. For 3 candidates, if a voter ranks Alice (index 0) first and Bob (index 1) second, then ranks[0] = 0 and ranks[1] = 1 .
After locking:
Winner: Bob Ranked Candidates: ['Bob', 'Alice', 'Charlie']
Logic : Iterate through each candidate and check the locked matrix. If there is no candidate Cs50 Tideman Solution
# Rank candidates by win count ranked_candidates = sorted(candidates, key=lambda x: win_counts[x], reverse=True)
If the cycle is detected, do not lock. If the path ends without hitting the target, lock it in. The CS50 Tideman solution implements a voting system
// Function to read input void read_input(int *voters, int *candidates, voter_t **voters_prefs) // Read in the number of voters and candidates scanf("%d %d", voters, candidates);
Count how many voters preferred candidate A over candidate B for every possible pair. The ranks array holds the order of candidates
This post will break down the problem, explain the logic of the locked array, and give you a clean, working solution with an explanation you can actually understand.
The first step is to record voter preferences. We use a 2D array, preferences[i][j]